Problem

1970 AHSME Problem 30

[asy] size(175); defaultpen(linewidth(0.8)); real r=50, a=4,b=2.5,c=6.25; pair A=origin,B=c*dir(r),D=(a,0),C=shift(b*dir(r))*D; draw(A--B--C--D--cycle); label("$A$",A,SW); label("$B$",B,N); label("$C$",C,E); label("$D$",D,S); label("$a$",D/2,N); label("$b$",(C+D)/2,NW); [/asy]

In the accompanying figure, segments AB and CD are parallel, the measure of \angle{D} is twice the measure of \angle{B}, and the measures of segments AB and CD are a and b respectively. Then the measure of AB is equal to

\textbf{(A) }\dfrac{1}{2}a+2b\qquad \textbf{(B) }\dfrac{3}{2}b+\dfrac{3}{4}a\qquad \textbf{(C) }2a-b\qquad \textbf{(D) }4b-\frac{1}{2}a\qquad \textbf{(E) }a+b


Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.


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