1971 AHSME Problem 25

A teen age boy wrote his own age after his father's. From this new four place number, he subtracted the absolute value of the difference of their ages to get 4,289. The sum of their ages was

\textbf{(A) }48\qquad \textbf{(B) }52\qquad \textbf{(C) }56\qquad \textbf{(D) }59\qquad \textbf{(E) }64

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.