Problem
1971 AHSME Problem 26
![[asy] size(2.5inch); pair A, B, C, E, F, G; A = (0,3); B = (-1,0); C = (3,0); E = (0,0); F = (1,2); G = intersectionpoint(B--F,A--E); draw(A--B--C--cycle); draw(A--E); draw(B--F); label("$A$",A,N); label("$B$",B,W); label("$C$",C,dir(0)); label("$E$",E,S); label("$F$",F,NE); label("$G$",G,SE); //Credit to chezbgone2 for the diagram[/asy]](/static/aops/6b2871ac00649198cedeac28106b8ab04545fd3d.png)
In \triangle ABC, point F divides side AC in the ratio 1:2. Let E be the point of intersection of side BC and AG where G is the midpoints of BF. The point E divides side BC in the ratio
\textbf{(A) }1:4\qquad \textbf{(B) }1:3\qquad \textbf{(C) }2:5\qquad \textbf{(D) }4:11\qquad \textbf{(E) }3:8
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