1971 AHSME Problem 29

Given the progression 10^{\dfrac{1}{11}}, 10^{\dfrac{2}{11}}, 10^{\dfrac{3}{11}}, 10^{\dfrac{4}{11}},\ldots , 10^{\dfrac{n}{11}}. The least positive integer n such that the product of the first n terms of the progression exceeds 100,000 is

\textbf{(A) }7\qquad \textbf{(B) }8\qquad \textbf{(C) }9\qquad \textbf{(D) }10\qquad \textbf{(E) }11

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.