Problem
1971 AHSME Problem 31
Quadrilateral ABCD is inscribed in a circle with side AD, a diameter of length 4. If sides AB and BC each have length 1, then side CD has length
\textbf{(A) }\frac{7}{2}\qquad \textbf{(B) }\frac{5\sqrt{2}}{2}\qquad \textbf{(C) }\sqrt{11}\qquad \textbf{(D) }\sqrt{13}\qquad \textbf{(E) }2\sqrt{3}
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