Problem
1988 AHSME Problem 14
For any real number a and positive integer k, define
{a \choose k} = \frac{a(a-1)(a-2)\cdots(a-(k-1))}{k(k-1)(k-2)\cdots(2)(1)}
What is
{-\frac{1}{2} \choose 100} \div {\frac{1}{2} \choose 100}?
\textbf{(A)}\ -199\qquad \textbf{(B)}\ -197\qquad \textbf{(C)}\ -1\qquad \textbf{(D)}\ 197\qquad \textbf{(E)}\ 199
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